Learn Quadrilaterals Pictures

The quadrilaterals are the two dimensional plane shapes which have four surfaces. Therefore it is a polygon with four sides. The sum of interior angle of a quadrilaterals are 360 degrees. There are two diagonals for each quadrilaterals. Since we have two diagonals in a quadrilaterals, both the diagonals will intersect at a common point. The regular quadrilaterals will have four edges and four vertices’. The lines of symmetry of a quadrilaterals are based on what sort of the quadrilaterals are. Let us learn about various quadrilaterals pictures.

Learn Pictures of a quadrilaterals 1:

Learn picture of Square:

• Square has 4 equal sides
• It has 4 equal angles
• Each angle of a square is a right angle
• It has 4 lines of symmetry
• Square is a regular shape

Learn Picture of a Rectangle:

 

• Rectangle has 2 pairs of equal sides
• It has 4 equal angles
• Each angle of a rectangle is a right angle
• It has 2 lines of symmetry
• Rectangle is an irregular shape

Learn Picture of a Parallelogram:

• Parallelogram has 2 pairs of equal sides
• It has 2 pairs of equal angles
• Opposite sides of a parallelogram are parallel
• It has NO lines of symmetry
• Parallelogram is an irregular shape

Learn Pictures of a quadrilaterals 2:

Learn picture of  Rhombus:

• Rhombus has 4 equal sides
• It has 2 pairs of equal angles
• Opposite sides of a rhombus are parallel
• It has 2 lines of symmetry
• Rhombus is an irregular shape

Learn Picture of a Trapezium:

 

• Trapezium has unequal sides
• One pair of opposite sides are parallel for a trapezium
• It is usually has NO lines of symmetry
• Trapezium is an irregular shape

Learn Picture of a Kite:

 

• Kite has 2 pairs of equal sides
• It has 1 pair of equal angles
• Equal sides of a kite are adjacent
• Kite has 1 line of symmetry
• Kite is an irregular shape

Chart Composite Numbers

It is an integer that has more than one prime factors. They can be expressed as unique set of prime numbers. The first composite number is 4. Besides 1 every other number is either prime or composite number. Besides 1 each other natural number is either prime or composite number. In chart composite number all the numbers will the composite numbers. so that we can find the composite numbers easily by seeing the chart.

Chart composite number upto 200:

4	50	91	130	170
6	51	92	132	171
8	52	93	133	172
9	54	94	134	174
10	55	95	135	175
12	56	96	136	179
14	57	98	138	177
15	58	99	140	178
16	60	100	141	180
18	62	102	142	182
20	63	104	143	183
21	64	105	144	184
22	65	106	145	185
24	66	108	146	186
25	68	110	147	187
26	69	111	148	189
27	70	112	150	190
28	72	114	152	192
30	74	115	153	194
32	75	116	154	195
33	76	117	155	196
34	77	118	156	199
35	78	119	158	200
36	80	120	159
38	81	121	160
39	82	122	161
40	84	123	162
42	85	124	164
45	86	125	165
46	87	126	166
48	88	128	168
49	90	129	169

Chart composite number upto 400:

201	243	288	329	370
202	244	289	330	371
203	245	290	332	372
204	246	291	333	374
205	247	292	334	375
206	248	294	335	376
207	250	295	336	377
208	252	296	338	378
209	253	297	339	380
210	254	298	340	381
212	255	299	341	382
213	256	300	342	384
214	258	301	343	385
215	259	302	344	386
216	260	303	345	387
217	261	304	346	388
218	262	305	348	390
219	264	306	350	391
220	265	306	351	392
221	266	309	352	393
222	267	310	354	394
224	268	312	355	395
225	270	314	356	396
226	272	315	357	398
228	273	318	358	399
230	274	319	360	400
231	275	320	361
232	276	321	362
234	277	322	363
235	280	323	364
236	282	324	365
237	284	325	366
238	285	326	367
240	286	327	368
242	287	328	369

90 Degree Right Angle

In geometry and trigonometry, a right angle is an angle that bisects the angle formed by two halves of a straight line. More precisely, if a ray is placed so that its endpoint is on a line and the adjacent angles are equal, then they are right angles.
A right triangle or right-angled triangle is a triangle in which one angle is a right angle (that is, a 90 degree angle).



The side opposite the right angle is called the hypotenuse (side c in the figure above). The sides adjacent to the right angle are called legs. (Source: from Wikipedia).It is shown in the figure.
Now, we are going to see some of the problems involving 90 degree right angle. From these problems, we can get clear view about 90 degree right angle.

90 degree right angle problems:

Example problem 1:
Using the diagram shown, Find the length of hypotenuse.

Given:

Right angle triangle

 a = 5cm and b = 5cm

Use the Pythagorean Theorem to find c.

c² = a² + b²

Substitute a = 5 and b = 5.

c² = 5² + 5²

c²=25+25

c²=50

Find the square root of each side.

C= √50=5 √2cm

Additional problems in 90 degree right angle:

Example problem 2:
Determine the length of the hypotenuse in the right angle triangle, given that angle θ = 37 degree.

Solution:

Sin θ= opposite side / hypotenuse

Sin 37 = 12 / x

0.6 = 12 / x

x = 12 / 0.6

x = 20

So, the side AC is 20cm.

Example problem 3:
Determine the length of the side x in the diagram, given that angle θ = 60 degree.

Solution:

Here, we use the sin θ. because the sin θ is related to the opposite side and hypotenuse.

Sin θ= opposite side / hypotenuse

Sin 60 = x / 24

0.866 = x / 24

x = 24* 0.866

x = 20.8

So, the side AC is 20.8cm.

Practice problems in right angle:
1) Find the length of hypotenuse when the adjacent side is 5 and the opposite side is 12. (Answer: hypotenuse=13)
2) Determine the length of the opposite side, given that angle θ = 30 degree and hypotenuse is 24. (Answer: opposite side= 12).

Alternate Segment Theorem

Given a circle and two points P and Q on its boundary and a departure to the circle at Q, then angle between the departure and the line PQ is the same as the angle subtended by this chord in segment of the circle on the opposite side of PQ.  Alternate segment theorem states that approach involving a departure and its chord is equal to angle in the alternate segment.Interactive animatronics representatives proof of an alternate segment theorem.

Theorem for alternative segment

         The length of the line segment AB, which joins A (x₁, y₁) and B (x₂, y₂) is given by
d= `|AB|=sqrt((x2-x1)^(2)+(y2-y1)^(2))`  
Proof:
Let A (x₁, y₁) and B (x₂, y₂) be two points in the plane.
Let d = distance between the points A and B.
Draw AL and BM perpendicular to x-axis (parallel to y-axis).
Draw AC perpendicular to BM to cut BM at C.

OL = x₁, OM = x₂ [AC = LM = OM - OL = x₂ - x₁]
MB = y₂, MC = LA = y₁ [CB = MB - MC = y₂ - y₁]
`AB^(2)=AC^(2)+CB^(2)`
`d^(2)=(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)`
d=`sqrt((x_(2)-x_(1))^(2)+(y_(2)-y_(1)^(2)))`

Alternate Segment Circle Theorem

           The chord CE divides the circle into 2 segments. Angle CEA and CDE are angles in alternate segments because they are in opposite segments. Circles are easy blocked curves which separate the plane into two regions, an interior and an exterior.The alternating segment theorem states that a position connecting a departure and a chord through the point of contact is equal to the angle in the alternate segment.
         In conditions of the beyond diagram, the alternating segment theorem tells us to facilitate angle CEA and angle CDE are equivalent.



A digression makes an angle of 90 degrees with the radius of a circle,so we know that ∠OAC + x = 90.
The angle in a semi-circle is 90, so ∠BCA = 90.
The angles in a triangle add up to 180, so ∠BCA + ∠OAC + y = 180.
Therefore 90 + ∠OAC + y = 180 and so ∠OAC + y = 90.
But OAC + x = 90, so ∠OAC + x = ∠OAC + y.
Hence x = y.

Fractions Addition

The whole thing is partitioned in two different pieces. Each piece is called fraction of the whole thing.A fraction represents the divided form of two numbers. It takes the general form of `(a)/(b)` . Here a represents the numerator value and b represents the denominator value. `(17)/(5)` is an example for fraction. Fractions are classified according to their values numerator and denominator which plays the important role in fractions addition table

Types of fraction

1.Proper Fraction

2.Improper Fraction

3.Mixed Fraction

4.Equivalent Fraction


Activities involved in fractions addition:

1. When we add two fractions with same denominator, those fractions are added directly.

For example:

`(2/3) + (7/3) = (2+7)/(3) = 9/3`   (here numerator is divided by denominator)

=3

2. When we add two fractions with different denominator, we have to find least common denominator.

`(2/3) + (6/9) = [(2xx3)+6]/(9) = (6+6)/(9) = (12)/(9)` (here numerator is divided by denominator)

=4/3

3. If mixed fraction is involved in fractions addition, we have to convert the mixed fraction to improper fraction. Then we have to check the denominators. If the denominators are different, we have to find least common denominator. Otherwise no problem.

2 ¾ + 5/4

Take the mixed fraction 2 ¾

Convert it to improper fraction as below

` [(2xx4)+3]/(4) = (8+3)/(4) = (11)/(4)`

Now we can do the fractions addition

`(11)/(4) + (5)/(4)= (11+5)/(4) = (16)/(4) = 4`

About Easy Vector Tutorial

Easy vector tutorial is process of tutoring to students in online by the tutors. Easy vector tutorial is the vectors which are specified by magnitude and direction. The examples of vectors are displacement, velocity, acceleration, momentum of force and weight. Easy vector tutorial is method  tutoring on vector problems in the online with basic steps and calculations. Tutor vista is the main website to provide online tutors to give easy vector tutorial.  The following problems are some of the examples of  easy vector tutorial process done by tutor vista.

Easy vector tutorial on example problems

Example problem 1: Add 2`veci` +6`vecj`+4`veck` with 5`veci`+2`vecj`+2`veck`
Solution
Place the vectors according to the magnitudes shown below.

    2`veci` + 6`vecj` +4`veck`

    5`veci` + 2`vecj` +2`veck`

   ---------------------------

    7`veci` + 8`vecj` + 6`veck`

   ----------------------------

Example problem 2: Subtract 5`veci` + 4`vecj`- 8`veck` with 4`veci`- 6`vecj` +3`veck`
Solution
Since we have the magnitudes in opposite direction it will be easy to perform method
    (5`veci` + 4`vecj`- 8`veck`4`veci`- 6`vecj` +3`veck`
    `(13 - 4)veci + (4-(-6))vecj + (-8-3)veck`
    `(13 - 4)veci + (4 + 6))vecj + (-8-3)veck`

    `(9) veci + (10)vecj + (-11) veck`

     `9 veci +10vecj -11 veck`

Example problem 3: Find the magnitude of `2 veci - vecj + 7 veck`
Solution:
Magnitude of `2veci - 3vecj + 7 veck = |2veci - 3vecj + 7 veck|`
                                                   = `sqrt((2)^2 + (-3)^2 + (7)^2)`
                                                   `sqrt(4+9+49)`
                                                  =`sqrt (62)`


Example problem 4: Find the sum of the vectors `veca - vecb + 2 vecc` and `2veca +3vecb - 4vecc` and also find the modulus of the sum.
Solution
Let  `vecx = veca - vecb + 2 vecc` ,      `vecy = 2veca + 3 vecb - 4vecc`
`vecx + vecy = (veca - vecb + 2 vecc) + (2veca + 3 vecb - 4vecc)`
             `= 3 veca +2vecb - 2 vecc`
`|vecx + vecy| = sqrt (3^2 + 2^2 + (-2)^2)`
               ` = sqrt (9+4+4)`
               ` = sqrt 17`

Easy vector tutorial on practce problems

1. Add 7`veca` +2`vecb`+3`vecc` with 2`veca`+3`vecb`+`3vecc`
Answer: 9`veca`+5`vecb`+6`vecc`
2. Subtract 4`veci` + 3`vecj`- 6`veck` with `veci`- 2`vecj` +2`veck`
Answer: `veci`+5`vecj` -8`veck`
3. Find the sum of the vectors `vecp -3 vecq + 2 vecr` and `3vecp +vecq - 2vecr` and also find the modulus of the sum.
Answer: 6

Geometric Mean

     The geometric mean is the mean or average which indicates the central tendency or typical value of a set of numbers. This is similar to arithmetic mean, which is the sum of adding the set of numbers and then dividing the sum of count number in set, n, and the number are multiplied and the nth root of resulting value is taken. The geometric mean only applies to positive numbers.

Formula Of Geometric Mean

Geometric Mean = ((X₁)(X₂)(X₃)........(X_N))^1/N
Where
              X = Individual score
              N = Sample size (Number of scores)
Geometric mean is also used for set of numbers whose values are multiplied together or exponential in nature, such as growth of growth of human population or interest rates of a financial investment. The geometric mean is one of the three classic Pythagorean means, aforementioned arithmetic mean and harmonic mean.

Calculation of Geometric Mean

 The geometric mean of data set [ a₁, a₂, --------, a_n ] is given by
^{$\left(\prod_{i = 1}^{n} a_{i}\right)^{1/n}$} = $ \sqrt[n]{a_{1}a_{2}......a_{n}}$
The geometric mean of a given set is less than or equal to the given set of arithmetic mean (the two mean of equal when all the members of a data set are equal) this allows the definition for arithmetic geometric mean the two values always lie in between the geometric mean is also arithmetic harmonic mean in that if two sequences (a_n) and (h_n) are defined:
a_{n + 1} =  $\frac{an + hn}{2}$ , a_o   = x and
h_{n + 1} = $\frac{2}{1/an + 1/bn}$, h_o = y.
Then a_n is converge to the geometric mean of x. h_n is converge to the geometric mean of y.
The sequence for converge to a common limit ( which can be shown by Bolzano - Weierstrass theorem) the geometric mean is given by
$\sqrt{a_{i}h_{i}}$  = $\sqrt{\frac{a_{i} + h{i}}{1/a_{i} + 1/h_{i}}}$  =  $ \sqrt{a_{i + 1}h_{i+1}}$

Exponential Growth of Geometric Mean

The geometric mean is more approximate than the arithmetic mean for explaining exponential growth.